yeah no :happysad:
dam the square root function on this is touchy
yeah no :happysad:
dam the square root function on this is touchy
but the slope is unknown also......
How can i have 2 variables? Why would the X value even fucking matter, and what x value????? 9, 5 is the value, what other x value is there???????
Well just use my formula and extrapolate backwards, X in my formula is slope, so plug into all the x's the formula using the x value that is used to find the slope.
the distance is the square root of x^2 - 18x +106
ok right now my best guess is:
L(x) = SQRT(x^2 + (5x/(x-9))^2)
it works at least when the slope is -1
and by distance i meant LENGTH SWNJDN FUCK YOWMEP
where is this x value?
god is correctQuote:
Originally Posted by God
for the love of all that is holy explain what you did
take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)
use the distance formula.
sqrt((x2-x1)^2 + (y2-y1)^2)
simplify.
you get my answer.
take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)
use the distance formula.
sqrt((x2-x1)^2 + (y2-y1)^2)
simplify.
you get my answer.
im pretty sure this is rightQuote:
Originally Posted by God
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God please explain to me what x value the L is being based on, the legth on X as in the base of the triangle? I swear to god my slope answer is 100% right, i don't understand what other x value there is...
and i specifically don't get how you can get the distance without knowing the slope!
hypotenuse = sqrt(x^2 + y^2)
so we know L(x) = the same. we want to find y.
draw the triagle and think about x varying and what happens to y, knowing that (9,5) is the 'pivot' so to speak. as x tends to infinity, y tends to 5. as x tends 9, y tends to inifity. 5x/(x-9) is a function consistent with those limits, so it's your y. plug it in and there you go.
god: high school drop out getting everyones college homework right this semester
how did you get y
oh limits
this is so wrong i want to KILL MYSELFQuote:
Originally Posted by Rayne
So its the X value of the base as in draw the x and y axis, and the x value is the length of the bottom side of the triangle? WHY DIDN'T THEY SAY THAT!
can we delete this thread and/or pretend it never existed
I still am sort of confused on how you get y.
I say we put it in the archives.
I love reading your math solving posts, they always make me laugh for just that reason.Quote:
Originally Posted by God
okQuote:
Originally Posted by Kirby
why was this moved out of the archives?
this is an old thread lol~