I kinda like arc, ^-1 kinda makes you want to make it a reciprocal not an inverse.
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I kinda like arc, ^-1 kinda makes you want to make it a reciprocal not an inverse.
well reciprocal and inverse means the same thing.........
I don't know about real definitions, but secant, cosecant, and cotangent are reciprocal functions, while arc functions are inverse functions that have nothing to do with switching the numerator and denominator, but instead the x and y.
NERDSSS!!!
Things me and God disagree about
-foreign policy
-Justin being funny
-arc vs ^-1
i dont know if you figured this out yet, but thats not how inverse functions workQuote:
cos(arccot(3/4) (there is a whole series of these, I think there is a trick I am missing, there is no regular radian for 3/4)
TOO MUCH MATH. STOP TALKING ABOUT MATH.
then help me God
cotangent inverse gives the angle of the cotangent with the contangent's value as its domain. use that and you can just draw a triangle and get A/H.
I am still confused, not considering cosine yet, the problem is basically cot (x) = 3/4, right? Im not quite sure for exactly cotangents work, but the only solutions I know for tangent are fractions on the basic unit circle (1, (sqrt(3)/2)/(1/2), the opposite of that, and 0). Please forgive me if I completely off, I haven't taken trig anything in over 2 years which is part of my problem.
also this may be important http://news.yahoo.com/mathematician-...131737044.html
it's asking for the cosine of the angle that makes cotangent 3/4. cotangent = A/O = 3/4.
do you mean adjacent / opposite
yeah uhh I still have no idea, I think I need to do some research on trig, because I couldn't even do this if it was tangent and my book gives no explaination
ok so I am physically looking at a triangle with a radian angle of 3 and a side of 4
uhhhhh do I can to like recreate this triagle, then find the cosine
isn't radian 3 over 90 degrees
ahhhh
adjacent not angle....
no.
the triangle has an angle, it can be either angle other than the 90 it really doesn't matter. its opposite sid is 4 and its adjacent side is 3.
so I am looking at a triangle with sides of 3, 4, and sqrt(21)
and looking at cos(x) = 3/sqrt(21)
right?
ew trigonometry bleh
Canadians use sin^-1, if that means anything
I was wondering what arcsin was until I read Rayne's post. Then I was like "Oh, sin^-1 !"
:(
whats f^-1(5)?
The f'(5) ?????? because thats simple dirivative + plugging in. what does f^-1 mean????
what is the function that you need to plug 5 into to get the original function back
arccos(2x)=arcsec(2x)
arcsec(x) = arccos(1/x) so
arccos(2x)=arccos(1/2x)
cos both sides.
2x=1/2x
4x^2=1
x=1/4 ???