Thread: Im having a massive brain fart at the moment and Hicky and Rayne are on

1. yeah no

dam the square root function on this is touchy

2. but the slope is unknown also......
How can i have 2 variables? Why would the X value even fucking matter, and what x value?? 9, 5 is the value, what other x value is there?

Well just use my formula and extrapolate backwards, X in my formula is slope, so plug into all the x's the formula using the x value that is used to find the slope.

3. the distance is the square root of x^2 - 18x +106

4. ok right now my best guess is:

L(x) = SQRT(x^2 + (5x/(x-9))^2)

it works at least when the slope is -1

5. and by distance i meant LENGTH SWNJDN FUCK YOWMEP

6. where is this x value?

7. Originally Posted by God
ok right now my best guess is:

L(x) = SQRT(x^2 + (5x/(x-9))^2)

it works at least when the slope is -1
god is correct

for the love of all that is holy explain what you did

8. take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)

use the distance formula.

sqrt((x2-x1)^2 + (y2-y1)^2)

simplify.

you get my answer.

9. take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)

use the distance formula.

sqrt((x2-x1)^2 + (y2-y1)^2)

simplify.

you get my answer.

10. Originally Posted by God
ok right now my best guess is:

L(x) = SQRT(x^2 + (5x/(x-9))^2)

it works at least when the slope is -1
im pretty sure this is right

11. fudhsiopxrhnqopwdmawp'odmaops;mfpa;nfpaf

12. God please explain to me what x value the L is being based on, the legth on X as in the base of the triangle? I swear to god my slope answer is 100% right, i don't understand what other x value there is...
and i specifically don't get how you can get the distance without knowing the slope!

13. hypotenuse = sqrt(x^2 + y^2)

so we know L(x) = the same. we want to find y.

draw the triagle and think about x varying and what happens to y, knowing that (9,5) is the 'pivot' so to speak. as x tends to infinity, y tends to 5. as x tends 9, y tends to inifity. 5x/(x-9) is a function consistent with those limits, so it's your y. plug it in and there you go.

14. god: high school drop out getting everyones college homework right this semester

15. how did you get y

16. oh limits

17. Originally Posted by Rayne
take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)

use the distance formula.

sqrt((x2-x1)^2 + (y2-y1)^2)

simplify.

you get my answer.
this is so wrong i want to KILL MYSELF

18. So its the X value of the base as in draw the x and y axis, and the x value is the length of the bottom side of the triangle? WHY DIDN'T THEY SAY THAT!

19. can we delete this thread and/or pretend it never existed

20. I still am sort of confused on how you get y.

21. I say we put it in the archives.

22. Originally Posted by God
god: high school drop out getting everyones college homework right this semester
I love reading your math solving posts, they always make me laugh for just that reason.

23. Originally Posted by Kirby
I say we put it in the archives.
ok

24. why was this moved out of the archives?

25. this is an old thread lol~

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