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Thread: Im having a massive brain fart at the moment and Hicky and Rayne are on

  1. #26
    princeso Kirby's Avatar
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    yeah no

    dam the square root function on this is touchy

  2. #27
    Registered Users Regular ElijahWyatt's Avatar
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    but the slope is unknown also......
    How can i have 2 variables? Why would the X value even fucking matter, and what x value?? 9, 5 is the value, what other x value is there?

    Well just use my formula and extrapolate backwards, X in my formula is slope, so plug into all the x's the formula using the x value that is used to find the slope.
    "As for me, all i know is that i know nothing"

  3. #28
    Registered Users Regular Rayne's Avatar
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    the distance is the square root of x^2 - 18x +106

  4. #29
    what about .. eyebrows God's Avatar
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    ok right now my best guess is:

    L(x) = SQRT(x^2 + (5x/(x-9))^2)

    it works at least when the slope is -1

  5. #30
    Registered Users Regular Rayne's Avatar
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    and by distance i meant LENGTH SWNJDN FUCK YOWMEP

  6. #31
    Registered Users Regular ElijahWyatt's Avatar
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    where is this x value?
    "As for me, all i know is that i know nothing"

  7. #32
    princeso Kirby's Avatar
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    Quote Originally Posted by God View Post
    ok right now my best guess is:

    L(x) = SQRT(x^2 + (5x/(x-9))^2)

    it works at least when the slope is -1
    god is correct

    for the love of all that is holy explain what you did

  8. #33
    Registered Users Regular Rayne's Avatar
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    take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)

    use the distance formula.

    sqrt((x2-x1)^2 + (y2-y1)^2)

    simplify.

    you get my answer.

  9. #34
    Registered Users Regular Rayne's Avatar
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    take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)

    use the distance formula.

    sqrt((x2-x1)^2 + (y2-y1)^2)

    simplify.

    you get my answer.

  10. #35
    what about .. eyebrows God's Avatar
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    Quote Originally Posted by God View Post
    ok right now my best guess is:

    L(x) = SQRT(x^2 + (5x/(x-9))^2)

    it works at least when the slope is -1
    im pretty sure this is right

  11. #36
    Registered Users Regular Rayne's Avatar
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    fudhsiopxrhnqopwdmawp'odmaops;mfpa;nfpaf

  12. #37
    Registered Users Regular ElijahWyatt's Avatar
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    God please explain to me what x value the L is being based on, the legth on X as in the base of the triangle? I swear to god my slope answer is 100% right, i don't understand what other x value there is...
    and i specifically don't get how you can get the distance without knowing the slope!
    "As for me, all i know is that i know nothing"

  13. #38
    what about .. eyebrows God's Avatar
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    hypotenuse = sqrt(x^2 + y^2)

    so we know L(x) = the same. we want to find y.

    draw the triagle and think about x varying and what happens to y, knowing that (9,5) is the 'pivot' so to speak. as x tends to infinity, y tends to 5. as x tends 9, y tends to inifity. 5x/(x-9) is a function consistent with those limits, so it's your y. plug it in and there you go.

  14. #39
    what about .. eyebrows God's Avatar
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    god: high school drop out getting everyones college homework right this semester

  15. #40
    princeso Kirby's Avatar
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    how did you get y

  16. #41
    princeso Kirby's Avatar
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    oh limits

  17. #42
    Registered Users Regular Rayne's Avatar
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    Quote Originally Posted by Rayne View Post
    take the point specified in the question (9, 5) and take the point where the line meets the x axis (x, 0)

    use the distance formula.

    sqrt((x2-x1)^2 + (y2-y1)^2)

    simplify.

    you get my answer.
    this is so wrong i want to KILL MYSELF

  18. #43
    Registered Users Regular ElijahWyatt's Avatar
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    So its the X value of the base as in draw the x and y axis, and the x value is the length of the bottom side of the triangle? WHY DIDN'T THEY SAY THAT!
    "As for me, all i know is that i know nothing"

  19. #44
    Registered Users Regular Rayne's Avatar
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    can we delete this thread and/or pretend it never existed

  20. #45
    princeso Kirby's Avatar
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    I still am sort of confused on how you get y.

  21. #46
    princeso Kirby's Avatar
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    I say we put it in the archives.

  22. #47
    In reverie, I felt you holding me. Dogar The Brave's Avatar
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    Quote Originally Posted by God View Post
    god: high school drop out getting everyones college homework right this semester
    I love reading your math solving posts, they always make me laugh for just that reason.

    Your an absolutely wonderful man, any girl that is yours is lucky and I know that from personal experience. ~KMT

  23. #48
    Vanity of vanities, all is vanity Hicky's Avatar
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    Quote Originally Posted by Kirby View Post
    I say we put it in the archives.
    ok

  24. #49
    princeso Kirby's Avatar
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    why was this moved out of the archives?

  25. #50
    Registered Users Regular ElijahWyatt's Avatar
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    this is an old thread lol~
    "As for me, all i know is that i know nothing"

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